如何用Scala将指定格式的数据写入到文件(scala,编程语言)

新建FileOps对象：

package com.ruozedata.day3

import java.io.{File,PrintWriter}

import java.text.SimpleDateFormat

import java.util.{Calendar, Date}

//import scala.io.Source

object FileOps {

def main(args: Array[String]): Unit = {

//文件读取

// val file = Source.fromFile("D:\\software\\data\\scalaIO.txt")

// file.foreach(print)

// file.close()getTracffic()

/**

* 文件格式：

* domain tracffic time

* www.ruozedata.com13781[2018-07-11 06:52:41]

*/

//文件写入

//加载文件D:\software\data\ScalaWriter.txt 如果没有会创建

val writer = new PrintWriter(new File("D:\\software\\data\\ScalaWriter.txt"))

writer.flush(); //清空文件内容

//输入标题字段：domain tracffic time

//writer.println("domain\ttracffic\ttime")

//定义网址的数组

val arr = Array("www.ruozedata.com","www.zhibo8.com","www.dongqiudi.com")

//定义26个字母的数组 用于随机写入tracffic字段的值（非数字）

val arr2 = Array("a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z")

//定义一个数字的集合

val arr3 = (10000 to 99999).toArray

//用于接收tracffic值的变量

var ele = ""

for(i <- 1 until 100000){

//如果 i为偶数就设置ele的值为数字，否则设置为字母

ele = if (i%10==0) arr2((new util.Random).nextInt(26)) else arr3((new util.Random).nextInt(arr3.length)).toString()

//将内容写入到文件里面

writer.println(arr((new util.Random).nextInt(3))+"\t"+ele+"\t"+(getNowDate()))

}

//关闭写入流

writer.close()

//获取动态时间的方法，格式：yyyy-MM-dd HH:mm:ss

def getNowDate(): String = {

// 动态获取日

var days = (new util.Random).nextInt(getNowMonthEnd()).toString() ;

// 动态获取小时

var hours = (new util.Random).nextInt(23).toString() ;

// 动态获取分钟

var minutes = (new util.Random).nextInt(59).toString() ;

// 动态获取秒

var seconds = (new util.Random).nextInt(59).toString() ;

//判断1-9的日需要在前面添加0

if (days == "0"){ // 如果获取的日为0，则需要手动处理成其他日，我这里处理成01

days = "01"

}else{

if ((days.length()) == 1) {

days = "0"+days

}

}

//判断1-9的日需要在前面添加0

hours = if (hours.length() == 1) "0"+hours else hours

//判断1-9的日需要在前面添加0

minutes = if (minutes.length() == 1) "0"+minutes else minutes

//判断1-9的日需要在前面添加0

seconds = if (seconds.length() == 1) "0"+seconds else seconds

//获取当前日期

val now: Date = new Date()

val dateFormat: SimpleDateFormat = new SimpleDateFormat("yyyy-MM")

//格式化当前日期 格式：yyyy-MM

val date = dateFormat.format(now)

//返回动态日期格式：[yyyy-MM-dd HH:mm:ss]

return "["+date+"-"+days+" "+hours+":"+minutes+":"+seconds+"]"

}

//获取当前月的最后一天的方法

def getNowMonthEnd():Int={

var period:String=""

var cal:Calendar =Calendar.getInstance();

var df:SimpleDateFormat = new SimpleDateFormat("dd");

cal.set(Calendar.DATE, 1)

cal.roll(Calendar.DATE,-1)

period=df.format(cal.getTime())//本月最后一天

Integer.parseInt(period)

}

}

}